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Mps br.timing: testlib randomize() was wrong (simply discarding the first 0..32000 values is a throughly defective way to seed the generator). correct it to simply use timestamp (modulo m) as the initial seed, and then iterate 10 times.
rnd(): add notes, and create rnd_verify() to confirm implementation is correct. Copied from Perforce Change: 167181 ServerID: perforce.ravenbrook.com
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1 changed files with 87 additions and 12 deletions
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@ -36,21 +36,73 @@ struct itimerspec; /* stop complaints from time.h */
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*
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* I nabbed it from "ML for the Working Programmer", originally from:
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* Stephen K Park & Keith W Miller (1988). Random number generators:
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* good one are to find. Communications of the ACM, 31:1192-1201.
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* good ones are hard to find. Communications of the ACM, 31:1192-1201.
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*
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* This is a 'full-period' generator: all values from [1..(mod-1)]
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* are returned once, and then the generator cycles round again.
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* (The value 0 is not part of the cycle and is never returned). That
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* means the period = mod-1, ie. 2147483646.
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*
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* This "x 16807 mod 2^31-1" generator has been very well studied.
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* It is not the 'best' (most random) simple generator, but it is
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* free of all vices we might care about for this application, so
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* we'll keep it simple and stick with this, thanks.
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*
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* There are faster implementations of this generator, summarised
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* briefly here:
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* - L. Schrage (1979 & 1983) showed how to do all the calculations
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* within 32-bit integers. See also Numerical recipes in C.
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* - David Carta (1990) showed how to also eliminate division.
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*/
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static unsigned long seed = 1;
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/* 2^31 - 1 == (1UL<<31) - 1 == 2147483647 */
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#define RND_MOD_2_31_1 2147483647
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#define RND_MOD_2_31_1_FLOAT 2147483647.0
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unsigned long rnd(void)
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{
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static unsigned long seed = 1;
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double s;
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s = seed;
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s *= 16807.0;
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s = fmod(s, 2147483647.0); /* 2^31 - 1 */
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s = fmod(s, RND_MOD_2_31_1_FLOAT); /* 2^31 - 1 */
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seed = (unsigned long)s;
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return seed;
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/* Have you modified this code? Run rnd_verify() please! RHSK */
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}
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/* rnd_verify -- verify that rnd() returns the correct results */
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static void rnd_verify(void)
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{
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unsigned long orig_seed = seed;
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unsigned long i;
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/* This test is from:
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* Stephen K Park & Keith W Miller (1988). Random number generators:
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* good ones are hard to find. Communications of the ACM, 31:1192-1201.
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* Note: The Park-Miller paper uses 1-based indices.
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*/
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i = 1;
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seed = 1;
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for(i = 2; i < 10001; i += 1) {
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(void)rnd();
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}
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Insist(i == 10001);
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Insist(rnd() == 1043618065);
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/* from Robin Whittle's compendium at
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* http://www.firstpr.com.au/dsp/rand31/
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* Observe wrap-around after 'full-period' (which excludes 0).
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* Note: uses 0-based indices, ie. rnd_0 = 1, rnd_1 = 16807, ...
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*/
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i = 2147483645;
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seed = 1407677000;
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i += 1;
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Insist(i == (1UL<<31) - 2 ); /* 'full-period' excludes 0 */
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Insist(rnd() == 1); /* wrap-around */
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seed = orig_seed;
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}
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/* rnd_addr -- a random address generator
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*
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@ -75,19 +127,42 @@ mps_addr_t rnd_addr(void)
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void randomize(int argc, char **argv)
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{
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int i, k, n;
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int n;
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unsigned long seed0;
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int i;
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if (argc > 1) {
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n = sscanf(argv[1], "%d", &k);
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die((n == 1) ? MPS_RES_OK : MPS_RES_FAIL, "randomize");
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n = sscanf(argv[1], "%lu", &seed0);
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Insist(n == 1);
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printf("randomize(): resetting initial seed to: %lu.\n", seed0);
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rnd_verify(); /* good to verify occasionally: slip it in here */
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} else {
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k = time(NULL) % 32000;
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printf("Randomizing %d times.\n", k);
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/* time_t uses an arbitrary encoding, but hopefully the low order */
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/* 31 bits will have at least one bit changed from run to run. */
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seed0 = 1 + time(NULL) % (RND_MOD_2_31_1 - 1);
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printf("randomize(): choosing initial seed: %lu.\n", seed0);
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}
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/* Randomize the random number generator a bit. */
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for (i = k; i > 0; --i)
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rnd();
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Insist(seed0 < RND_MOD_2_31_1); /* 2^31 - 1 */
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Insist(seed0 != 0);
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seed = seed0;
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/* The 'random' seed is taken from time(), which may simply be a
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* count of seconds: therefore successive runs may start with
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* nearby seeds, possibly differing only by 1. So the first value
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* returned by rnd() may differ by only 16807. It is conceivable
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* that some tests might be able to 'spot' this pattern (for
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* example: by using the first rnd() value, mod 100M and rounded
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* to multiple of 128K, as arena size).
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*
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* So to mix it up a bit, we do a few iterations now. How many?
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* Very roughly, 16807^2 is of the same order as 2^31, so two
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* iterations would make the characteristic difference similar to
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* the period. Hey, let's go wild and do 10.
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*/
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for(i = 0; i < 10; i += 1) {
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(void)rnd();
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}
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}
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@ -146,7 +221,7 @@ void cdie(int res, const char *s)
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/* C. COPYRIGHT AND LICENSE
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*
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* Copyright (C) 2001-2002 Ravenbrook Limited <http://www.ravenbrook.com/>.
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* Copyright (C) 2001-2002, 2008 Ravenbrook Limited <http://www.ravenbrook.com/>.
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* All rights reserved. This is an open source license. Contact
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* Ravenbrook for commercial licensing options.
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*
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