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(diary-float): Rewritten to fix bug when base date

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of entry and entry date are in different months.
Added optional parameter DAY.
(list-sexp-diary-entries): Revise description of diary-float.
This commit is contained in:
Richard M. Stallman 1997-05-20 05:18:15 +00:00
parent 151eeaa7c4
commit 9b58d14443
1 changed files with 57 additions and 12 deletions
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69
lisp/calendar/diary-lib.el
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@ -940,12 +940,14 @@ A number of built-in functions are available for this type of diary entry:
can be lists of integers, the constant t, or an integer.
The constant t means all values.
%%(diary-float MONTH DAYNAME N) text
%%(diary-float MONTH DAYNAME N &optional DAY) text
Entry will appear on the Nth DAYNAME of MONTH.
(DAYNAME=0 means Sunday, 1 means Monday, and so on;
if N is negative it counts backward from the end of
the month. MONTH can be a list of months, a single
month, or t to specify all months.
month, or t to specify all months. Optional DAY means
Nth DAYNAME of MONTH on or after/before DAY. DAY defaults
to 1 if N>0 and the last day of the month if N<0.
%%(diary-block M1 D1 Y1 M2 D2 Y2) text
Entry will appear on dates between M1/D1/Y1 and M2/D2/Y2,
@ -1166,19 +1168,62 @@ D1, M1, Y1, D2, M2, Y2 if `european-calendar-style' is t."
(if (and (<= date1 d) (<= d date2))
entry)))
(defun diary-float (month dayname n)
(defun diary-float (month dayname n &optional day)
"Floating diary entry--entry applies if date is the nth dayname of month.
Parameters are MONTH, DAYNAME, N. MONTH can be a list of months, the constant
t, or an integer. The constant t means all months. If N is negative, count
backward from the end of the month."
(let ((m (extract-calendar-month date))
(y (extract-calendar-year date)))
(if (and
(or (and (listp month) (memq m month))
(equal m month)
(eq month t))
(calendar-date-equal date (calendar-nth-named-day n dayname m y)))
entry)))
backward from the end of the month.
An optional parameter DAY means the Nth DAYNAME on or after/before MONTH DAY."
;; This is messy because the diary entry may apply, but the date on which it
;; is based can be in a different month/year. For example, asking for the
;; first Monday after December 30. For large values of |n| the problem is
;; more grotesque.
(and (= dayname (calendar-day-of-week date))
(let* ((m (extract-calendar-month date))
(d (extract-calendar-day date))
(y (extract-calendar-year date))
(limit; last (n>0) or first (n<0) possible base date for entry
(calendar-nth-named-absday (- n) dayname m y d))
(last-abs (if (> n 0) limit (+ limit 6)))
(first-abs (if (> n 0) (- limit 6) limit))
(last (calendar-gregorian-from-absolute last-abs))
(first (calendar-gregorian-from-absolute first-abs))
; m1, d1 is first possible base date
(m1 (extract-calendar-month first))
(d1 (extract-calendar-day first))
(y1 (extract-calendar-year first))
; m2, d2 is last possible base date
(m2 (extract-calendar-month last))
(d2 (extract-calendar-day last))
(y2 (extract-calendar-year last)))
(or (and (= m1 m2); only possible base dates in one month
(or (and (listp month) (memq m1 month))
(= m1 month)
(eq month t))
(let ((d (or day (if (> n 0)
1
(calendar-last-day-of-month m1 y1)))))
(and (<= d1 day) (<= day d2))))
(and (< m1 m2); only possible base dates straddle two months
(or
; m1, d1 works is a base date
(and
(or (and (listp month) (memq m1 month))
(= m1 month)
(eq month t))
(<= d1 (or day (if (> n 0)
1
(calendar-last-day-of-month m1 y1)))))
; m2, d2 works is a base date
(and (or (and (listp month) (memq m2 month))
(= m2 month)
(eq month t))
(<= (or day (if (> n 0)
1
(calendar-last-day-of-month m2 y2)))
d2)))))
entry)))
(defun diary-anniversary (month day year)
"Anniversary diary entry.